浅念
42 lines
1.4 KiB
Python
42 lines
1.4 KiB
Python
"""职能边界破防率观测(只读): AI 回复中出现"价格形态数字"的轮次占比。
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方案B(输出过滤)的启动依据: >10% 即砌墙。锚定式匹配,年份/续航数字天然不命中。"""
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import re
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import sqlite3
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import sys
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DB = sys.argv[1] if len(sys.argv) > 1 else "./data/cc_ai_kefu.db"
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PATTERNS = [
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(r"\$\s?\d", "美元符"),
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(r"\d[\d,.]*\s*(usd|美元|万块?|块钱)", "货币单位"),
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(r"(price|cost|quote)[^.\d]{0,20}(?<![a-z])(?!(?:19|20)\d\d(?!\d))\d",
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"价格动词邻接(年份/车型编号排除)"),
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(r"\d[\d,.]*\s*k\b(?!\w)", "25k形式"),
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]
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COMPILED = [(re.compile(p, re.I), name) for p, name in PATTERNS]
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def main() -> None:
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conn = sqlite3.connect(f"file:{DB}?mode=ro", uri=True)
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rows = conn.execute(
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"SELECT conversation_id, content FROM messages WHERE role='assistant'"
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).fetchall()
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hits = []
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for cid, content in rows:
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text = content or ""
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for pattern, name in COMPILED:
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if pattern.search(text):
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hits.append((cid, name, text[:60]))
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break
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for cid, name, preview in hits:
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print(f" [{name}] conv={cid[:8]} {preview}")
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total = len(rows)
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rate = len(hits) / total * 100 if total else 0
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print(f"AI回复总轮次: {total} | 价格形态命中: {len(hits)} ({rate:.0f}%)")
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print("← 破防率。>10% 启动方案B(输出过滤)")
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conn.close()
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if __name__ == "__main__":
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main()
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