fix(management): 期聚合active_friends按(uid,peer)去重——多账号共享客户不再双计;reply计数并入Python/单一METRIC_VERSION
Co-Authored-By: Claude Code <noreply@anthropic.com>
This commit is contained in:
@@ -26,7 +26,6 @@ import datetime as dt
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import statistics
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from collections import namedtuple
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from collections.abc import Iterable
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from zoneinfo import ZoneInfo
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import sqlalchemy as sa
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from sqlalchemy.ext.asyncio import AsyncSession
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@@ -38,11 +37,9 @@ from app.db.models import (
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MsgDailyStats,
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Staff,
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)
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from app.storage.employee_metrics import METRIC_VERSION
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from app.storage.staff_summary import account_map
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_SH = ZoneInfo("Asia/Shanghai")
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METRIC_VERSION = "v1"
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PeriodMetrics = namedtuple("PeriodMetrics", [
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"user_id", "days_with_data", "msg_sent", "msg_recv", "cust_threads",
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"threads_answered", "fr_sum_ms", "fr_p50_ms", "fr_p90_ms",
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@@ -226,7 +223,7 @@ async def period_metrics(
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a["cooling_customer"] = int(cool or 0)
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a["dormant_customer"] = int(dorm or 0)
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# ---- fact 分位 + 2h/24h 回复计数(同一过滤) ----
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# ---- fact 分位 + 2h/24h 回复计数(同一过滤,Python 侧一次聚合) ----
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fr_conds = [FirstReplyFact.day.between(start_day, end_day)]
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if channel is not None:
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fr_conds.append(FirstReplyFact.channel == channel)
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@@ -244,26 +241,11 @@ async def period_metrics(
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for uid, frs in fr_by_user.items():
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acc[uid]["fr_p50_ms"] = _percentile(frs, 1, 2)
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acc[uid]["fr_p90_ms"] = _percentile(frs, 9, 10)
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# 2h/24h 计数与分位同源同窗——回复率分子分母口径一致
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acc[uid]["reply_2h_count"] = sum(1 for fr in frs if fr <= 7_200_000)
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acc[uid]["reply_24h_count"] = sum(1 for fr in frs if fr <= 86_400_000)
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reply = (await session.execute(
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sa.select(
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FirstReplyFact.owner_account_id.label("owner"),
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sa.func.sum(sa.case(
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(FirstReplyFact.fr_ms <= 7_200_000, 1), else_=0
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)).label("c2h"),
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sa.func.sum(sa.case(
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(FirstReplyFact.fr_ms <= 86_400_000, 1), else_=0
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)).label("c24h"),
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).where(*fr_conds).group_by(FirstReplyFact.owner_account_id)
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)).all()
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for owner, c2h, c24h in reply:
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uid = amap.get(owner or "")
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if uid is None or uid not in target:
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continue
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acc[uid]["reply_2h_count"] += int(c2h or 0)
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acc[uid]["reply_24h_count"] += int(c24h or 0)
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# ---- distinct 活跃客户:窗内 (owner, peer) 去重(friend 行) ----
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# ---- distinct 活跃客户:账号归并到员工后按 peer 去重 ----
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af_conds = [
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MsgDailyStats.day.between(start_day, end_day),
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MsgDailyStats.peer_kind == "friend",
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@@ -274,12 +256,14 @@ async def period_metrics(
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sa.select(MsgDailyStats.owner_account_id, MsgDailyStats.peer_id)
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.distinct().where(*af_conds)
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)).all()
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active: dict[str, set[tuple[str, str]]] = {}
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active: dict[str, set[str]] = {}
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for owner, peer in pairs:
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uid = amap.get(owner or "")
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if uid is None or uid not in target:
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continue
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active.setdefault(uid, set()).add((owner or "", peer or ""))
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# (uid, peer) 粒度:同一员工多账号(wx1+wx2)的共享客户只计 1
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# ——与宽表日值口径一致(storage 侧账号归并后 add(peer))
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active.setdefault(uid, set()).add(peer or "")
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for uid, pset in active.items():
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acc[uid]["active_friends"] = len(pset)
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@@ -6,7 +6,8 @@
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- 宽表 SUM 按 (day∈窗, metric_version='v1', channel) 过滤;
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active_rooms_avg 摊到全窗天数(含无数据日);
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- 期末生命周期存量=每 (user, channel) 最新 ≤end 行,跨渠道相加;
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- distinct 活跃客户=窗内 (owner, peer) 去重(peer_kind='friend');
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- distinct 活跃客户=窗内 (uid, peer) 去重(peer_kind='friend')——
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同一员工多账号的共享客户只计 1(与宽表日值口径一致);
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- 窗口工具:闭区间 day_range/等长前窗/28 天个人基线窗;
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- 幽灵员工(不在 staff)过滤;user_ids 交集;通话恒全渠道。
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"""
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@@ -159,6 +160,22 @@ async def test_distinct_active_cross_day(make_session):
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assert m["u1"].active_friends == 2
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async def test_active_friends_shared_peer_across_accounts(make_session):
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"""多账号共享客户去重:u1 的 wx1/wx3 都会话 p1 → active_friends=1
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(账号归并到员工后按 peer 去重,非 (owner, peer) 双计)。"""
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s = make_session
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await _seed_org(s)
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s.add(WechatAccount(wx_id="wx3", user_id="u1"))
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await s.commit()
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for owner in ("wx1", "wx3"):
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s.add(MsgDailyStats(channel="wechat", owner_account_id=owner,
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peer_kind="friend", peer_id="p1", day=20260901))
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await s.commit()
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m = await period_metrics(s, 20260901, 20260905, "wechat")
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assert m["u1"].active_friends == 1
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assert m["u2"].active_friends == 0
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def test_window_helpers():
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# day_range 闭区间 + 月末边界
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assert day_range(20260901, 20260903) == [20260901, 20260902, 20260903]
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@@ -193,6 +210,7 @@ async def test_ghost_and_channel_none(make_session):
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assert set(m) == {"u1", "u2"} # ghost 不在;零数据 u2 在
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u1 = m["u1"]
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assert u1.msg_sent == 7 # 两渠道行都归 u1
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assert u1.days_with_data == 1 # 双渠道同日只计 1 天(DISTINCT day)
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assert u1.fr_p50_ms == 100_000 # [100s,300s] 合并后 ceil(0.5*2)=1
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assert u1.fr_p90_ms == 300_000 # ceil(0.9*2)=2
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assert u1.reply_2h_count == 2
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